mathematics – TIling 7×107 rectangle with heptominoes
Is it possible to tile a 7×107 rectangle with the 107 heptominoes that do not have a hole?
Obviously, the heptomino with a hole cannot be used to tile, and there are 107 remaining heptominoes?
Rules:
- Each heptomino must be used exactly once
- No overlap or gaps allowed
- Heptominoes can be reflected
- All heptominoes must have the same area
Easy mode if you don’t want too much of a challenge: computer-puzzle
Hard mode if you want a challenge: no-computers